This is the simple inverter 100W which use CD4047 CMOS IC as signal generator and MOSFET transistor IRF540 as signal amplifier. Field Effect Transistor (FET) is better than ordinary transistor in both stability and responsibility. You’ll need a 2-3A center tapped transformer to deliver 100W power output.
IRF540 has specifically been designed to minimize input capacitance and gate charge. It is therefore suitable as primary switch in advanced highefficiency, high-frequency isolated DC-DC converters for Telecom and Computer applications. It is also intended for any applications with low gate drive requirements.
The CMOS IC CD4047B acts as multivibrator to generate a frequency. It capable of operating in either the monostable or astable mode. It requires an external capacitor (between pins 1 and 3) and an external resistor (between pins 2 and 3) to determine the output pulse width in the monostable mode, and the output frequency in the astable mode.
![[Tested] Simple Inverter Circuit 12V DC to 230V AC MOSFET](https://i0.wp.com/inverter-circuit.com/wp-content/uploads/2016/10/Tested-Inverter-Circuit-Design.jpg?resize=200%2C135&ssl=1 "Tested Inverter Circuit Design")
RE: 100 W inverter using CD4047
Respectfully, this inverter circuit does not work because the CD4047 is not a gate driver but just a simple multivibrator. A gate driver on the other hand, such as the IR2153 for instance, provides the required dead time between shutdown of mosfet 1 and startup of mosfet 2. Without that dead time one ends up with shoot through (cross conduction) across both mosfets, resulting in the destruction of at least the mosfets. Any half bridge of full bridge requires the use of a gate driver in order to safely drive the transistors. The CD 4047 is not designed for that purpose.
Kind regards,
Peter